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35x^2-115x+30=0
a = 35; b = -115; c = +30;
Δ = b2-4ac
Δ = -1152-4·35·30
Δ = 9025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9025}=95$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-115)-95}{2*35}=\frac{20}{70} =2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-115)+95}{2*35}=\frac{210}{70} =3 $
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